What is the domain of f(x)=1+1/x-x/(x-1) ?

The domain of f(x)=1+1/x-x/(x-1) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=1+1/x-x/(x-1)

domain

f (x) = 1 + \frac{1}{x} - \frac{x}{x - 1}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1

The function domain

x < 0 or 0 < x < 1 or x > 1

f (x) = e^{\frac{1}{x}} x^{2} + 2 x

f (x) = \frac{3 x ^{2} + 9}{2 x ^{2} - 16}

f (x) = \frac{ln ( x + 5 )}{ln ( 2 )} + 3

f (x) = x - 3 + 5

\frac{x - 16}{2 ( x - 8 ) x - 8}

What is the domain of f(x)=1+1/x-x/(x-1) ?
The domain of f(x)=1+1/x-x/(x-1) is x<0\lor 0<x<1\lor x>1