What is the domain of f(x)=(sqrt(x+3))/(x^2-36) ?

The domain of f(x)=(sqrt(x+3))/(x^2-36) is -3 6

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domain of f(x)=(sqrt(x+3))/(x^2-36)

domain

f (x) = \frac{x + 3}{x ^{2} - 36}

- 3 \leq x < 6 or x > 6

Interval Notation

[- 3, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 6, x = - 6

Combine real regions and undefined points for final function domain

- 3 \leq x < 6 or x > 6

f (x) = lo g_{10} (2 x - 12)

f (x) = 1.5

f (x) = 1 + \frac{1}{x} - \frac{x}{x - 1}

f (x) = e^{\frac{1}{x}} x^{2} + 2 x

f (x) = \frac{3 x ^{2} + 9}{2 x ^{2} - 16}

What is the domain of f(x)=(sqrt(x+3))/(x^2-36) ?
The domain of f(x)=(sqrt(x+3))/(x^2-36) is -3<= x<6\lor x>6