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Frequently Asked Questions (FAQ)
What is the inverse of F(s)=(3-s)/(s^2-4s+7) ?
- The inverse of F(s)=(3-s)/(s^2-4s+7) is (4s-1+sqrt(-12s^2+4s+1))/(2s),(4s-1-sqrt(-12s^2+4s+1))/(2s)