We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the inverse of f(x)=(100)/(1+20e^{-0.05x)} ?
- The inverse of f(x)=(100)/(1+20e^{-0.05x)} is -(ln(\frac{100-x)/(20x))}{0.05}