What is the f(x)=(9x^2-1)/(6x^3-x|3-2x|-1) ?

The f(x)=(9x^2-1)/(6x^3-x|3-2x|-1) is

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f(x)=(9x^2-1)/(6x^3-x|3-2x|-1)

f (x) = \frac{9 x ^{2} - 1}{6 x ^{3} - x ∣ 3 - 2 x ∣ - 1}

Domain : x < - \frac{1}{2} or - \frac{1}{2} < x < - \frac{1}{3} or - \frac{1}{3} < x < \frac{1}{2} or x > \frac{1}{2}

X Intercepts : (\frac{1}{3}, 0), Y Intercepts : (0, 1)

Asymptotes : Vertical x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal y = 0

Extreme Points : None

Solution steps

Domain of

\frac{9 x ^{2} - 1}{6 x ^{3} - x ∣ 3 - 2 x ∣ - 1} : x < - \frac{1}{2} or - \frac{1}{2} < x < - \frac{1}{3} or - \frac{1}{3} < x < \frac{1}{2} or x > \frac{1}{2}

Axis interception points of

\frac{9 x ^{2} - 1}{6 x ^{3} - x ∣ 3 - 2 x ∣ - 1} :

X Intercepts

: (\frac{1}{3}, 0),

Y Intercepts

: (0, 1)

Asymptotes of

\frac{9 x ^{2} - 1}{6 x ^{3} - x ∣ 3 - 2 x ∣ - 1} :

Vertical

: x = - \frac{1}{2}, x = \frac{1}{2},

Horizontal

: y = 0

Extreme Points of

\frac{9 x ^{2} - 1}{6 x ^{3} - x ∣ 3 - 2 x ∣ - 1} :

None

f (x) = (x^{3} - 1)^{2}

f (k) = 2 k^{2}

y = x^{2} + x - 1

f (x) = - 0.5 x^{2} + 7 x - 3

y = 1 + \frac{1}{x}

What is the f(x)=(9x^2-1)/(6x^3-x|3-2x|-1) ?
The f(x)=(9x^2-1)/(6x^3-x|3-2x|-1) is