What is the derivative of (x^2-2x+4/(x-2)) ?

The derivative of (x^2-2x+4/(x-2)) is (x^2-4x)/((x-2)^2)

What is the first derivative of (x^2-2x+4/(x-2)) ?

The first derivative of (x^2-2x+4/(x-2)) is (x^2-4x)/((x-2)^2)

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\frac{d}{d x} (\frac{x ^{2} - 2 x + 4}{x - 2})

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 2 x + 4}{x - 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 2 x + 4 ) ( x - 2 ) - \frac{d}{d x} ( x - 2 ) ( x ^{2} - 2 x + 4 )}{( x - 2 ) ^{2}}

\frac{d}{d x} (x^{2} - 2 x + 4) = 2 x - 2

\frac{d}{d x} (x - 2) = 1

= \frac{( 2 x - 2 ) ( x - 2 ) - 1 \cdot ( x ^{2} - 2 x + 4 )}{( x - 2 ) ^{2}}

Simplify

\frac{( 2 x - 2 ) ( x - 2 ) - 1 \cdot ( x ^{2} - 2 x + 4 )}{( x - 2 ) ^{2}} : \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

= \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

x \to \infty lim (x^{- x})

\int_{0}^{2} x (x^{2} + 1)^{5} d x

v^{2} (2 v + 1)

\frac{d}{d x} (\frac{x ^{2} ln ( x )}{e ^{x}})

\int_{0}^{4} cos (x) d x

What is the derivative of (x^2-2x+4/(x-2)) ?
The derivative of (x^2-2x+4/(x-2)) is (x^2-4x)/((x-2)^2)
What is the first derivative of (x^2-2x+4/(x-2)) ?
The first derivative of (x^2-2x+4/(x-2)) is (x^2-4x)/((x-2)^2)