What is the solution for 3(1+x^2)y^'=2xy(y^3-1) ?

The solution for 3(1+x^2)y^'=2xy(y^3-1) is y=\sqrt[3]{1/(1-x^2e^{3c_{1)}-e^{3c_{1}}}}

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3(1+x^2)y^'=2xy(y^3-1)

3 (1 + x^{2}) y^{^{'}} = 2 x y (y^{3} - 1)

Solution steps

3 (1 + x^{2}) y^{'} (x) = 2 x y (y^{3} - 1)

Solve separable ODE:

f (t) = 2 - \frac{4}{t}, (4, 1)

\frac{d}{d x} (x^{2} + \frac{a ^{4}}{x ^{2}})

\frac{d y}{d x} = \frac{x - 1}{y - 4}

\frac{d}{d x} (\frac{x - 4}{x})

n = 1 \sum \infty \frac{1}{4 n}

What is the solution for 3(1+x^2)y^'=2xy(y^3-1) ?
The solution for 3(1+x^2)y^'=2xy(y^3-1) is y=\sqrt[3]{1/(1-x^2e^{3c_{1)}-e^{3c_{1}}}}