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Frequently Asked Questions (FAQ)
What is the solution for y^{''}+5y^'+6y=1+2t+3t^2 ?
- The solution for y^{''}+5y^'+6y=1+2t+3t^2 is y=c_{1}e^{-2t}+c_{2}e^{-3t}+(t^2)/2-t/2+5/12