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Popular >

area y=x^4-4x^2,y=x^2-4

Solution

area

y = x^{4} - 4 x^{2}, y = x^{2} - 4

Solution

8

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{4} - 4 x^{2} - (x^{2} - 4) d x

Solve

\int_{- 2}^{2} x^{4} - 4 x^{2} - (x^{2} - 4) d x : 8

The area is:

= 8

Popular Examples

y^'=(x^4)/(16)(e^{-y})

y^{^{'}} = \frac{x ^{4}}{16} (e^{- y})

integral of 2/(3x-4)

\int \frac{2}{3 x - 4} d x

derivative of x(1-x^3)

\frac{d}{d x} (x (1 - x)^{3})

integral from 1 to 3 of (9^x-7^x)

\int_{1}^{3} (9^{x} - 7^{x}) d x

derivative of (x^2-2/(x^2+2))

\frac{d}{d x} (\frac{x ^{2} - 2}{x ^{2} + 2})

Frequently Asked Questions (FAQ)

What is area y=x^4-4x^2,y=x^2-4 ?
The answer to area y=x^4-4x^2,y=x^2-4 is 8