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Frequently Asked Questions (FAQ)
What is the solution for y''(t)+6y'(t)+25y=0,y(0)=1,y'(0)=-1 ?
- The solution for y''(t)+6y'(t)+25y=0,y(0)=1,y'(0)=-1 is y=e^{-3t}(cos(4t)+1/2 sin(4t))