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Frequently Asked Questions (FAQ)
What is the solution for y^{''}+14y^'+49y=0,y(-4)=-1,y(-4)=5 ?
- The solution for y^{''}+14y^'+49y=0,y(-4)=-1,y(-4)=5 is y=e^{-7t-28}(-1+4e^{28}c_{2})+c_{2}e^{-7t}t