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Frequently Asked Questions (FAQ)
What is the solution for y^{''}-4y^'-5y=0,y(1)=0,y^'(1)=9 ?
- The solution for y^{''}-4y^'-5y=0,y(1)=0,y^'(1)=9 is y=(3e^{5t-5})/2-(3e)/2 e^{-t}