We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the tangent of f(x)=sqrt(x-1) ?
- The tangent of f(x)=sqrt(x-1) is y= 1/(2sqrt(a_{0)-1)}x+sqrt(a_{0)-1}-(a_{0})/(2sqrt(a_{0)-1)}