What is the solution for (dx)/(dy)=3e^{2x-3y} ?

The solution for (dx)/(dy)=3e^{2x-3y} is x=-(ln(2e^{-3y}-c_{1}))/2

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(dx)/(dy)=3e^{2x-3y}

\frac{d x}{d y} = 3 e^{2 x - 3 y}

x = - \frac{ln ( 2 e ^{- 3 y} - c _{1} )}{2}

Solution steps

\frac{d x}{d y} = 3 e^{2 x - 3 y}

Solve separable ODE:

x = - \frac{ln ( 2 e ^{- 3 y} - c _{1} )}{2}

x = - \frac{ln ( 2 e ^{- 3 y} - c _{1} )}{2}

x d y - (y + 4) d x = 0

\frac{d y}{d x} = 14 e^{5 x - y}, y (0) = 0

\frac{d y}{d t} = \frac{( 3 t ^{2} + 4 t + 2 )}{2 ( y - 1 )}

(x^{2} + y^{2}) (x d y + y d x) - x y (x d x + y d y) = 0

y^{^{'}} - x (y - 1) = 0

What is the solution for (dx)/(dy)=3e^{2x-3y} ?
The solution for (dx)/(dy)=3e^{2x-3y} is x=-(ln(2e^{-3y}-c_{1}))/2