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Frequently Asked Questions (FAQ)
What is the solution for (ydy)/(dt)=(1+y^2)t^2 ?
- The solution for (ydy)/(dt)=(1+y^2)t^2 is y=sqrt(e^{(2t^3)/3+c_{1)}-1},y=-sqrt(e^{(2t^3)/3+c_{1)}-1}