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Frequently Asked Questions (FAQ)
What is the derivative of (c_{1}+c_{2}xe^{-3x}) ?
- The derivative of (c_{1}+c_{2}xe^{-3x}) is c_{2}e^{-3x}-3e^{-3x}(c_{1}+c_{2}x)
What is the first derivative of (c_{1}+c_{2}xe^{-3x}) ?
- The first derivative of (c_{1}+c_{2}xe^{-3x}) is c_{2}e^{-3x}-3e^{-3x}(c_{1}+c_{2}x)