What is the derivative of (w*vtx^2+x)/(x^2+2x+7) ?

The derivative of (w*vtx^2+x)/(x^2+2x+7) is (vtx^2)/(x^2+2x+7)

What is the first derivative of (w*vtx^2+x)/(x^2+2x+7) ?

The first derivative of (w*vtx^2+x)/(x^2+2x+7) is (vtx^2)/(x^2+2x+7)

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derivative of

\frac{w \cdot v t x ^{2} + x}{x ^{2} + 2 x + 7}

\frac{v t x ^{2}}{x ^{2} + 2 x + 7}

Solution steps

\frac{d}{d w} (\frac{w v t x ^{2} + x}{x ^{2} + 2 x + 7})

Treat

v, t, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{x ^{2} + 2 x + 7} \frac{d}{d w} (w v t x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{x ^{2} + 2 x + 7} (\frac{d}{d w} (w v t x^{2}) + \frac{d x}{d w})

\frac{d}{d w} (w v t x^{2}) = v t x^{2}

\frac{d x}{d w} = 0

= \frac{1}{x ^{2} + 2 x + 7} (v t x^{2} + 0)

Simplify

\frac{1}{x ^{2} + 2 x + 7} (v t x^{2} + 0) : \frac{v t x ^{2}}{x ^{2} + 2 x + 7}

= \frac{v t x ^{2}}{x ^{2} + 2 x + 7}

\frac{d}{d r} (3.14 r^{3})

y = 5 x^{2} - 6 x + 12

(9 x^{8} - 8 x^{9}) (\frac{x + 1}{x})

lo g_{10} (2^{x} + 2^{- x})

\frac{d}{d n} (i^{2 n})

What is the derivative of (w*vtx^2+x)/(x^2+2x+7) ?
The derivative of (w*vtx^2+x)/(x^2+2x+7) is (vtx^2)/(x^2+2x+7)
What is the first derivative of (w*vtx^2+x)/(x^2+2x+7) ?
The first derivative of (w*vtx^2+x)/(x^2+2x+7) is (vtx^2)/(x^2+2x+7)