What is the derivative of 4-3u^2 ?

The derivative of 4-3u^2 is -6u

What is the first derivative of 4-3u^2 ?

The first derivative of 4-3u^2 is -6u

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derivative of

4 - 3 u^{2}

- 6 u

Solution steps

\frac{d}{d u} (4 - 3 u^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (4) - \frac{d}{d u} (3 u^{2})

\frac{d}{d u} (4) = 0

\frac{d}{d u} (3 u^{2}) = 6 u

= 0 - 6 u

Simplify

= - 6 u

60 t^{2} - 60 t

13 e^{- x}

x^{x} - 100

\frac{( x + 6 )}{x}

ln (\frac{9}{x})