What is the derivative of (64)/(x^3) ?

The derivative of (64)/(x^3) is -(192)/(x^4)

What is the first derivative of (64)/(x^3) ?

The first derivative of (64)/(x^3) is -(192)/(x^4)

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derivative of

\frac{64}{x ^{3}}

- \frac{192}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{64}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 64 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 64 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 64 (- 3 x^{- 3 - 1})

Simplify

64 (- 3 x^{- 3 - 1}) : - \frac{192}{x ^{4}}

= - \frac{192}{x ^{4}}

f (x) = x^{3} + 1

\frac{8 x}{3}

\frac{- 1}{( s - 1 ) ^{2}}

y = x^{3} + 4 x^{2} + 5 x + 7

cos^{2} (x) + sin (x)

What is the derivative of (64)/(x^3) ?
The derivative of (64)/(x^3) is -(192)/(x^4)
What is the first derivative of (64)/(x^3) ?
The first derivative of (64)/(x^3) is -(192)/(x^4)