What is the tangent of f(x)=6x-x^2,\at x=0 ?

The tangent of f(x)=6x-x^2,\at x=0 is y=6x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=6x-x^2,\at x=0

tangent of

f (x) = 6 x - x^{2}, at x = 0

y = 6 x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = 6 x - x^{2} : \frac{df ( x )}{d x} = 6 - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(0, 0) : y = 6 x

y = 6 x

f (t) = 80 t + t^{2} - \frac{1}{48} t^{3}

- 4 x + x^{2} + 10, 12 - 5 x, 4 x - 6

\int_{1}^{16} \frac{8}{x} d x

\frac{d}{d x} ((2 + 3 x) (3 - 2 x))

f (x) = e^{- 4 x}

What is the tangent of f(x)=6x-x^2,\at x=0 ?
The tangent of f(x)=6x-x^2,\at x=0 is y=6x