What is the limit as x approaches 1+of sqrt(1-x^2) ?

The limit as x approaches 1+of sqrt(1-x^2) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1+of sqrt(1-x^2)

x \to 1 + lim (1 - x^{2})

0

Solution steps

x \to 1 + lim (1 - x^{2})

Plug in the value

x = 1

= 1 - 1^{2}

Simplify

= 0

\int_{\frac{1}{7}}^{3} 6 x ln (7 x) d x

3 e^{x} + x

\frac{d ^{2} y}{d x ^{2}} - 8 x^{2} = 0

t \cdot \frac{d y}{d t} = t^{3} + 13 t^{3} y

\int e^{x} cos (2 e^{x}) d x

What is the limit as x approaches 1+of sqrt(1-x^2) ?
The limit as x approaches 1+of sqrt(1-x^2) is 0