What is (\partial)/(\partial x)(2x^4y^5+3x^3y^5) ?

The answer to (\partial)/(\partial x)(2x^4y^5+3x^3y^5) is 8y^5x^3+9y^5x^2

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(\partial)/(\partial x)(2x^4y^5+3x^3y^5)

\frac{\partial}{\partial x} (2 x^{4} y^{5} + 3 x^{3} y^{5})

8 y^{5} x^{3} + 9 y^{5} x^{2}

Solution steps

\frac{\partial}{\partial x} (2 x^{4} y^{5} + 3 x^{3} y^{5})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{4} y^{5}) + \frac{\partial}{\partial x} (3 x^{3} y^{5})

\frac{\partial}{\partial x} (2 x^{4} y^{5}) = 8 y^{5} x^{3}

\frac{\partial}{\partial x} (3 x^{3} y^{5}) = 9 y^{5} x^{2}

= 8 y^{5} x^{3} + 9 y^{5} x^{2}

2 y^{^{''}} + 12 y^{^{'}} + 50 y = 0

- \frac{13}{s ^{6}}

\int e^{5 θ} d θ

\int - cos^{2} (2 x) d x

y^{^{'}} + t^{2} = 0

What is (\partial)/(\partial x)(2x^4y^5+3x^3y^5) ?
The answer to (\partial)/(\partial x)(2x^4y^5+3x^3y^5) is 8y^5x^3+9y^5x^2