What is (\partial)/(\partial v)(uv-v) ?

The answer to (\partial)/(\partial v)(uv-v) is u-1

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(\partial)/(\partial v)(uv-v)

\frac{\partial}{\partial v} (uv - v)

u - 1

Solution steps

\frac{\partial}{\partial v} (uv - v)

Treat

u

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial v} (uv) - \frac{\partial}{\partial v} (v)

\frac{\partial}{\partial v} (uv) = u

\frac{\partial}{\partial v} (v) = 1

= u - 1

(1 + e^{2 t})^{2}

\int x^{2} cosh (m x) d x

\frac{\partial}{\partial x} (2 x^{4} y^{5} + 3 x^{3} y^{5})

2 y^{^{''}} + 12 y^{^{'}} + 50 y = 0

- \frac{13}{s ^{6}}

What is (\partial)/(\partial v)(uv-v) ?
The answer to (\partial)/(\partial v)(uv-v) is u-1