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Popular >

derivative of y=-tcos(t)-t

Solution

derivative of

y = - t cos (t) - t

Solution

- cos (t) + t sin (t) - 1

Solution steps

\frac{d}{d t} (- t cos (t) - t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (t cos (t)) - \frac{d t}{d t}

\frac{d}{d t} (t cos (t)) = cos (t) - t sin (t)

\frac{d t}{d t} = 1

= - (cos (t) - t sin (t)) - 1

Simplify

= - cos (t) + t sin (t) - 1

Graph

Popular Examples

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\frac{d}{d x} (sin (x) ln (sec (x) + tan (x)) - 1)

integral from-2 to 2 of 1/(y^2-9)

\int_{- 2}^{2} \frac{1}{y ^{2} - 9} d y

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\frac{d}{d x} (\frac{sin ( x )}{y ^{2}})

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\frac{1}{2 x} + \frac{1}{5 x ^{\frac{4}{5}}}

integral from 0 to 1 of t/(t^2+1)

\int_{0}^{1} \frac{t}{t ^{2} + 1} d t

Frequently Asked Questions (FAQ)

What is the derivative of y=-tcos(t)-t ?
The derivative of y=-tcos(t)-t is -cos(t)+tsin(t)-1
What is the first derivative of y=-tcos(t)-t ?
The first derivative of y=-tcos(t)-t is -cos(t)+tsin(t)-1