What is the limit as x approaches-0+of 1/(3x) ?

The limit as x approaches-0+of 1/(3x) is infinity

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limit as x approaches-0+of 1/(3x)

x \to - 0 + lim (\frac{1}{3 x})

\infty

Solution steps

x \to - 0 + lim (\frac{1}{3 x})

For

x

approaching

- 0

from the right

, x > - 0 \Rightarrow 3 x > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{d}{d x} ((3 x^{2} - 13)^{3})

\int - 2 π tan^{5} (π x) sec^{3} (π x) d x

y = - t cos (t) - t

\frac{d}{d x} (sin (x) ln (sec (x) + tan (x)) - 1)

\int_{- 2}^{2} \frac{1}{y ^{2} - 9} d y

What is the limit as x approaches-0+of 1/(3x) ?
The limit as x approaches-0+of 1/(3x) is infinity