en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

14x+(dy)/(dx)=0

Solution

14 x + \frac{d y}{d x} = 0

Solution

y = - 7 x^{2} + c_{1}

Solution steps

14 x + \frac{d y}{d x} = 0

Substitute

\frac{d y}{d x}

with

y^{'} (x)

14 x + y^{^{'}} (x) = 0

Isolate

y^{'} (x) : y^{'} (x) = - 14 x

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 14 x d x

\int - 14 x d x = - 7 x^{2} + c_{1}

y = - 7 x^{2} + c_{1}

Graph

Popular Examples

(dy)/(dx)=4y^2sec^2(2x)

\frac{d y}{d x} = 4 y^{2} sec^{2} (2 x)

derivative of g(x)=-8e^{x^2-1}derivative of

g (x) = - 8 e^{x^{2} - 1}

integral of (6x+7)/((9x^2+21x)^3)

\int \frac{6 x + 7}{( 9 x ^{2} + 21 x ) ^{3}} d x

y^'=1-(4y)/(100)

y^{^{'}} = 1 - \frac{4 y}{100}

inverse oflaplace (e^{-spi})/((s)^2+1)inverse laplace

\frac{e ^{- s π}}{( s ) ^{2} + 1}

Frequently Asked Questions (FAQ)

What is the solution for 14x+(dy)/(dx)=0 ?
The solution for 14x+(dy)/(dx)=0 is y=-7x^2+c_{1}