What are the solutions to the equation x^2+16x-22=0 ?

The solutions to the equation x^2+16x-22=0 are x=-8+sqrt(86),x=-8-sqrt(86)

Find the zeros of x^2+16x-22=0

The zeros of x^2+16x-22=0 are x=-8+sqrt(86),x=-8-sqrt(86)

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x^{2} + 16 x - 22 = 0

x = - 8 + 86, x = - 8 - 86

Decimal Notation

x = 1.27361 \dots, x = - 17.27361 \dots

Solution steps

x^{2} + 16 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 22) = 286

x_{1, 2} = \frac{- 16 \pm 2 86}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 86}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 86}{2 \cdot 1}

x = \frac{- 16 + 2 86}{2 \cdot 1} : - 8 + 86

x = \frac{- 16 - 2 86}{2 \cdot 1} : - 8 - 86

The solutions to the quadratic equation are:

x = - 8 + 86, x = - 8 - 86

3 x + 4 > \frac{1}{3} (x - 2)

\frac{- 3 - 6 i}{8 + 8 i}

5 x^{2} + 16 x + 3

244

9 t^{2} - 30 t + 25

What are the solutions to the equation x^2+16x-22=0 ?
The solutions to the equation x^2+16x-22=0 are x=-8+sqrt(86),x=-8-sqrt(86)
Find the zeros of x^2+16x-22=0
The zeros of x^2+16x-22=0 are x=-8+sqrt(86),x=-8-sqrt(86)