What are the solutions to the equation x^2-20x+64=0 ?

The solutions to the equation x^2-20x+64=0 are x=16,x=4

Find the zeros of x^2-20x+64=0

The zeros of x^2-20x+64=0 are x=16,x=4

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x^{2} - 20 x + 64 = 0

x = 16, x = 4

Solution steps

x^{2} - 20 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 64 = 12

x_{1, 2} = \frac{- ( - 20 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 12}{2 \cdot 1}

x = \frac{- ( - 20 ) + 12}{2 \cdot 1} : 16

x = \frac{- ( - 20 ) - 12}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 16, x = 4

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a^{7} a^{4}

x + 13 \leq - \frac{1}{2} or x + 13 \geq \frac{1}{2}

0. 3^{5}

What are the solutions to the equation x^2-20x+64=0 ?
The solutions to the equation x^2-20x+64=0 are x=16,x=4
Find the zeros of x^2-20x+64=0
The zeros of x^2-20x+64=0 are x=16,x=4