What are the solutions to the equation x^2-18x+57=0 ?

The solutions to the equation x^2-18x+57=0 are x=9+2sqrt(6),x=9-2sqrt(6)

Find the zeros of x^2-18x+57=0

The zeros of x^2-18x+57=0 are x=9+2sqrt(6),x=9-2sqrt(6)

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x^{2} - 18 x + 57 = 0

x = 9 + 26, x = 9 - 26

Decimal Notation

x = 13.89897 \dots, x = 4.10102 \dots

Solution steps

x^{2} - 18 x + 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 57}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 57 = 46

x_{1, 2} = \frac{- ( - 18 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 4 6}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 4 6}{2 \cdot 1}

x = \frac{- ( - 18 ) + 4 6}{2 \cdot 1} : 9 + 26

x = \frac{- ( - 18 ) - 4 6}{2 \cdot 1} : 9 - 26

The solutions to the quadratic equation are:

x = 9 + 26, x = 9 - 26

4 x + 8 + 5 \leq 3

3 x - 5 - 4 - x > 1

x^{2} = 21 + 4 x

x^{2} + 10 x y - 24 y^{2}

3 y^{2} - 19 y - 14

What are the solutions to the equation x^2-18x+57=0 ?
The solutions to the equation x^2-18x+57=0 are x=9+2sqrt(6),x=9-2sqrt(6)
Find the zeros of x^2-18x+57=0
The zeros of x^2-18x+57=0 are x=9+2sqrt(6),x=9-2sqrt(6)