What are the solutions to the equation 5w^2-5w=0 ?

The solutions to the equation 5w^2-5w=0 are w=1,w=0

Find the zeros of 5w^2-5w=0

The zeros of 5w^2-5w=0 are w=1,w=0

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5 w^{2} - 5 w = 0

w = 1, w = 0

Solution steps

5 w^{2} - 5 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 5)^{2} - 4 \cdot 5 \cdot 0 = 5

w_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 5}, w_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 5}

w = \frac{- ( - 5 ) + 5}{2 \cdot 5} : 1

w = \frac{- ( - 5 ) - 5}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

w = 1, w = 0

\frac{1}{2} (- 2)

- 6 x \geq 36

\frac{a ^{2} - 81}{81 - 9 a}

- 6 x + 8 x = - 46

What are the solutions to the equation 5w^2-5w=0 ?
The solutions to the equation 5w^2-5w=0 are w=1,w=0
Find the zeros of 5w^2-5w=0
The zeros of 5w^2-5w=0 are w=1,w=0