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Popular >

x^3-8x^2+12x<= 0

Solution

x^{3} - 8 x^{2} + 12 x \leq 0

Solution

x \leq 0 or 2 \leq x \leq 6

+1

Interval Notation

(- \infty, 0] \cup [2, 6]

Solution steps

x^{3} - 8 x^{2} + 12 x \leq 0

Factor

x^{3} - 8 x^{2} + 12 x : x (x - 2) (x - 6)

x (x - 2) (x - 6) \leq 0

Identify the intervals

x \leq 0 or 2 \leq x \leq 6

Popular Examples

6x^2-4x-2<= 9x^2-15x+6

6 x^{2} - 4 x - 2 \leq 9 x^{2} - 15 x + 6

simplify (4x^{-4})^{-1/2}simplify

(4 x^{- 4})^{- \frac{1}{2}}

simplify 1+21000000/49000000 simplify

1 + \frac{21000000}{49000000}

5 x = 1 - 3 x^{2}

simplify 2(2/3)^2+5(2/3)+6 simplify

2 (\frac{2}{3})^{2} + 5 (\frac{2}{3}) + 6

Frequently Asked Questions (FAQ)

What is x^3-8x^2+12x<= 0 ?
The solution to x^3-8x^2+12x<= 0 is x<= 0\lor 2<= x<= 6