What are the solutions to the equation 2(x-5)^2=22 ?

The solutions to the equation 2(x-5)^2=22 are x=sqrt(11)+5,x=-sqrt(11)+5

Find the zeros of 2(x-5)^2=22

The zeros of 2(x-5)^2=22 are x=sqrt(11)+5,x=-sqrt(11)+5

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2 (x - 5)^{2} = 22

x = 11 + 5, x = - 11 + 5

Decimal Notation

x = 8.31662 \dots, x = 1.68337 \dots

Solution steps

2 (x - 5)^{2} = 22

Divide both sides by

2

(x - 5)^{2} = 11

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 11 : x = 11 + 5

Solve

x - 5 = - 11 : x = - 11 + 5

The solutions to the quadratic equation are:

x = 11 + 5, x = - 11 + 5

10 x - 3 x^{2} - 8 = 0

2 x + 8 > 16

5 - 9 (8 - 2 x) \leq 2 x - 115

2 x^{2} - 6 x

5 = \frac{2 x + 21}{3}

What are the solutions to the equation 2(x-5)^2=22 ?
The solutions to the equation 2(x-5)^2=22 are x=sqrt(11)+5,x=-sqrt(11)+5
Find the zeros of 2(x-5)^2=22
The zeros of 2(x-5)^2=22 are x=sqrt(11)+5,x=-sqrt(11)+5