What are the solutions to the equation (2.8*10^{-13})=x(0.013+x) ?

The solutions to the equation (2.8*10^{-13})=x(0.013+x) are x=0,x=-0.013

Find the zeros of (2.8*10^{-13})=x(0.013+x)

The zeros of (2.8*10^{-13})=x(0.013+x) are x=0,x=-0.013

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(2.8 \cdot 1 0^{- 13}) = x (0.013 + x)

x = 0, x = - 0.013

Solution steps

(2.8 \cdot 1 0^{- 13}) = x (0.013 + x)

Switch sides

x (0.013 + x) = (2.8 \cdot 1 0^{- 13})

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 0.013 + x = 0

Solve

0.013 + x = 0 : x = - 0.013

The solutions to the quadratic equation are:

x = 0, x = - 0.013

10 x + x^{2} = 24

\frac{3 + 4 i}{5 i}

\frac{5}{2} + \frac{1}{4}

25 6^{\frac{- 3}{4}}

11 x^{2} + 10 = 13

What are the solutions to the equation (2.8*10^{-13})=x(0.013+x) ?
The solutions to the equation (2.8*10^{-13})=x(0.013+x) are x=0,x=-0.013
Find the zeros of (2.8*10^{-13})=x(0.013+x)
The zeros of (2.8*10^{-13})=x(0.013+x) are x=0,x=-0.013