What are the solutions to the equation w^2-2w-3=0 ?

The solutions to the equation w^2-2w-3=0 are w=3,w=-1

Find the zeros of w^2-2w-3=0

The zeros of w^2-2w-3=0 are w=3,w=-1

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w^{2} - 2 w - 3 = 0

w = 3, w = - 1

Solution steps

w^{2} - 2 w - 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

w_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, w_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

w = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

w = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

w = 3, w = - 1

25 - v^{2}

13 - 14 a \leq 13 - 3 a

1^{\frac{1}{3}} \cdot 1^{\frac{1}{3}}

\frac{9 x ^{5} y ^{16}}{45 x ^{5} y ^{4}}

4 x^{3} - x^{2} + 12 x - 3

What are the solutions to the equation w^2-2w-3=0 ?
The solutions to the equation w^2-2w-3=0 are w=3,w=-1
Find the zeros of w^2-2w-3=0
The zeros of w^2-2w-3=0 are w=3,w=-1