What are the solutions to the equation 4v^2=-12v-9 ?

The solutions to the equation 4v^2=-12v-9 are v=-3/2

Find the zeros of 4v^2=-12v-9

The zeros of 4v^2=-12v-9 are v=-3/2

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4 v^{2} = - 12 v - 9

v = - \frac{3}{2}

Decimal Notation

v = - 1.5

Solution steps

4 v^{2} = - 12 v - 9

Move

9

to the left side

4 v^{2} + 9 = - 12 v

Move

12 v

to the left side

4 v^{2} + 9 + 12 v = 0

Write in the standard form

a x^{2} + b x + c = 0

4 v^{2} + 12 v + 9 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

v_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

v = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

v = - \frac{3}{2}

The solution to the quadratic equation is:

v = - \frac{3}{2}

4 = - 0.8 n

- 4 y = - 16

3 \leq 2 x + 7 \leq 1

x^{2} - 8 x - 12 = 0

4 (x + 6) - (4 x + 24) = 0

What are the solutions to the equation 4v^2=-12v-9 ?
The solutions to the equation 4v^2=-12v-9 are v=-3/2
Find the zeros of 4v^2=-12v-9
The zeros of 4v^2=-12v-9 are v=-3/2