What are the solutions to the equation v^2-2v-15=0 ?

The solutions to the equation v^2-2v-15=0 are v=5,v=-3

Find the zeros of v^2-2v-15=0

The zeros of v^2-2v-15=0 are v=5,v=-3

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v^{2} - 2 v - 15 = 0

v = 5, v = - 3

Solution steps

v^{2} - 2 v - 15 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

v_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, v_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

v = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

v = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

v = 5, v = - 3

22 - 2

\frac{8}{89}

23 - 2

- 2 i \cdot 2 i

\frac{9 x - 4}{2} = \frac{4 x + 3}{7}

What are the solutions to the equation v^2-2v-15=0 ?
The solutions to the equation v^2-2v-15=0 are v=5,v=-3
Find the zeros of v^2-2v-15=0
The zeros of v^2-2v-15=0 are v=5,v=-3