What is 9v+2>= 6v+8\lor-10-8v>3v-10 ?

The solution to 9v+2>= 6v+8\lor-10-8v>3v-10 is v = 2

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9v+2>= 6v+8\lor-10-8v>3v-10

9 v + 2 \geq 6 v + 8 or - 10 - 8 v > 3 v - 10

v < 0 or v \geq 2

Interval Notation

(- \infty, 0) \cup [2, \infty)

Solution steps

9 v + 2 \geq 6 v + 8 or - 10 - 8 v > 3 v - 10

9 v + 2 \geq 6 v + 8 : v \geq 2

- 10 - 8 v > 3 v - 10 : v < 0

Combine the intervals

v \geq 2 or v < 0

Merge Overlapping Intervals

v < 0 or v \geq 2

\frac{\frac{1}{2}}{\frac{1}{2}}

- 3 = a - 11

\frac{3}{2} - \frac{1}{3}

6 (3 x + 1)^{2} - 4 = 8

x - 3 \leq 7

What is 9v+2>= 6v+8\lor-10-8v>3v-10 ?
The solution to 9v+2>= 6v+8\lor-10-8v>3v-10 is v<0\lor v>= 2