What are the solutions to the equation x^2-8=7x ?

The solutions to the equation x^2-8=7x are x=8,x=-1

Find the zeros of x^2-8=7x

The zeros of x^2-8=7x are x=8,x=-1

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x^{2} - 8 = 7 x

x = 8, x = - 1

Solution steps

x^{2} - 8 = 7 x

Move

7 x

to the left side

x^{2} - 8 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 7 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

x = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

x = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 8, x = - 1

∣ x ∣ + 1 < 3

\frac{4 ^{6}}{4 ^{8}}

\frac{2 a}{4} + \frac{3 a}{7} + \frac{4 a}{14}

\frac{5}{x} + 5 \geq 0

\frac{1}{2} (2 x - 5) > \frac{x}{3} + 6

What are the solutions to the equation x^2-8=7x ?
The solutions to the equation x^2-8=7x are x=8,x=-1
Find the zeros of x^2-8=7x
The zeros of x^2-8=7x are x=8,x=-1