What is (7^{-2}m^0)/(n^{-4)} ?

The solution to (7^{-2}m^0)/(n^{-4)} is (n^4)/(49)

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simplify (7^{-2}m^0)/(n^{-4)}

simplify

\frac{7 ^{- 2} m ^{0}}{n ^{- 4}}

\frac{n ^{4}}{49}

Solution steps

\frac{7 ^{- 2} m ^{0}}{n ^{- 4}}

Simplify

7^{- 2} m^{0} : \frac{1}{49}

= \frac{\frac{1}{49}}{n ^{- 4}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{49 n ^{- 4}}

Simplify

49 n^{- 4} : \frac{49}{n ^{4}}

= \frac{1}{\frac{49}{n ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{n ^{4}}{49}

(- 3 x y^{5})^{2} (x^{3} y)^{- 1}

\frac{8 π}{180}

- 3 x^{2} + 33 x - 72

\frac{20}{45}

3 (x + 2) = 12

What is (7^{-2}m^0)/(n^{-4)} ?
The solution to (7^{-2}m^0)/(n^{-4)} is (n^4)/(49)