What are the solutions to the equation 2x^2+5x=9x-5 ?

The solutions to the equation 2x^2+5x=9x-5 are x=1+isqrt(3/2),x=1-isqrt(3/2)

Find the zeros of 2x^2+5x=9x-5

The zeros of 2x^2+5x=9x-5 are x=1+isqrt(3/2),x=1-isqrt(3/2)

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2 x^{2} + 5 x = 9 x - 5

x = 1 + i \frac{3}{2}, x = 1 - i \frac{3}{2}

Solution steps

2 x^{2} + 5 x = 9 x - 5

Move

5

to the left side

2 x^{2} + 5 x + 5 = 9 x

Move

9 x

to the left side

2 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

(- 4)^{2} - 4 \cdot 2 \cdot 5 : 26 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 2} : 1 + i \frac{3}{2}

x = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 2} : 1 - i \frac{3}{2}

The solutions to the quadratic equation are:

x = 1 + i \frac{3}{2}, x = 1 - i \frac{3}{2}

h^{2} + 8^{2} = 1 7^{2}

1 - 81 x^{8}

125 - 27 w^{3}

x^{3} - 8 x^{2} + 25 x - 26

3 x^{2} + 14 x + 15 = 0

What are the solutions to the equation 2x^2+5x=9x-5 ?
The solutions to the equation 2x^2+5x=9x-5 are x=1+isqrt(3/2),x=1-isqrt(3/2)
Find the zeros of 2x^2+5x=9x-5
The zeros of 2x^2+5x=9x-5 are x=1+isqrt(3/2),x=1-isqrt(3/2)