What are the solutions to the equation 16x^2+16x+4=81 ?

The solutions to the equation 16x^2+16x+4=81 are x= 7/4 ,x=-11/4

Find the zeros of 16x^2+16x+4=81

The zeros of 16x^2+16x+4=81 are x= 7/4 ,x=-11/4

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16 x^{2} + 16 x + 4 = 81

x = \frac{7}{4}, x = - \frac{11}{4}

Decimal Notation

x = 1.75, x = - 2.75

Solution steps

16 x^{2} + 16 x + 4 = 81

Move

81

to the left side

16 x^{2} + 16 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 16 ( - 77 )}{2 \cdot 16}

1 6^{2} - 4 \cdot 16 (- 77) = 72

x_{1, 2} = \frac{- 16 \pm 72}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 16 + 72}{2 \cdot 16}, x_{2} = \frac{- 16 - 72}{2 \cdot 16}

x = \frac{- 16 + 72}{2 \cdot 16} : \frac{7}{4}

x = \frac{- 16 - 72}{2 \cdot 16} : - \frac{11}{4}

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - \frac{11}{4}

\frac{a ^{7}}{a ^{5}}

\frac{4}{5}

2 x (x + 2) - 3 (2 + x)

2 x^{2} + 5 x = 9 x - 5

h^{2} + 8^{2} = 1 7^{2}

What are the solutions to the equation 16x^2+16x+4=81 ?
The solutions to the equation 16x^2+16x+4=81 are x= 7/4 ,x=-11/4
Find the zeros of 16x^2+16x+4=81
The zeros of 16x^2+16x+4=81 are x= 7/4 ,x=-11/4