What are the solutions to the equation w^2=14w ?

The solutions to the equation w^2=14w are w=14,w=0

Find the zeros of w^2=14w

The zeros of w^2=14w are w=14,w=0

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w^{2} = 14 w

w = 14, w = 0

Solution steps

w^{2} = 14 w

Move

14 w

to the left side

w^{2} - 14 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 0 = 14

w_{1, 2} = \frac{- ( - 14 ) \pm 14}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 14 ) + 14}{2 \cdot 1}, w_{2} = \frac{- ( - 14 ) - 14}{2 \cdot 1}

w = \frac{- ( - 14 ) + 14}{2 \cdot 1} : 14

w = \frac{- ( - 14 ) - 14}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

w = 14, w = 0

4 x^{2} + 33 x = 27

6 (x - 1) < 3 x - 5

21 = \frac{t ^{2} - t}{2}

(13 n^{2} + 11 n - 2 n^{4}) + (- 13 n^{2} - 3 n - 6 n^{4})

\frac{1}{9 ^{8}}

What are the solutions to the equation w^2=14w ?
The solutions to the equation w^2=14w are w=14,w=0
Find the zeros of w^2=14w
The zeros of w^2=14w are w=14,w=0