What are the solutions to the equation pir^2=20 ?

The solutions to the equation pir^2=20 are r=(2sqrt(5))/(sqrt(pi)),r=-(2sqrt(5))/(sqrt(pi))

Find the zeros of pir^2=20

The zeros of pir^2=20 are r=(2sqrt(5))/(sqrt(pi)),r=-(2sqrt(5))/(sqrt(pi))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

π r^{2} = 20

r = \frac{2 5}{π}, r = - \frac{2 5}{π}

Decimal Notation

r = 2.52313 \dots, r = - 2.52313 \dots

Solution steps

π r^{2} = 20

Divide both sides by

π

r^{2} = \frac{20}{π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{20}{π}, r = - \frac{20}{π}

\frac{20}{π} = \frac{2 5}{π}

- \frac{20}{π} = - \frac{2 5}{π}

r = \frac{2 5}{π}, r = - \frac{2 5}{π}

z^{2} - 5 z - 14

(- 4 k^{4} + 14 + 3 k^{2}) + (- 3 k^{4} - 14 k^{2} - 8)

2 a - \frac{a ^{2}}{2} = 1

x (a + 2) - a - 2 + 3 (a + 29)

6 x^{2} - x = x - 6

What are the solutions to the equation pir^2=20 ?
The solutions to the equation pir^2=20 are r=(2sqrt(5))/(sqrt(pi)),r=-(2sqrt(5))/(sqrt(pi))
Find the zeros of pir^2=20
The zeros of pir^2=20 are r=(2sqrt(5))/(sqrt(pi)),r=-(2sqrt(5))/(sqrt(pi))