What is ((2ab-a))/((4b^2-4b+1)) ?

The solution to ((2ab-a))/((4b^2-4b+1)) is a/(2b-1)

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simplify ((2ab-a))/((4b^2-4b+1))

simplify

\frac{( 2 ab - a )}{( 4 b ^{2} - 4 b + 1 )}

\frac{a}{2 b - 1}

Solution steps

\frac{2 ab - a}{4 b ^{2} - 4 b + 1}

Factor out common term

a

= \frac{a ( 2 b - 1 )}{4 b ^{2} - 4 b + 1}

Factor

4 b^{2} - 4 b + 1 : (2 b - 1)^{2}

= \frac{a ( 2 b - 1 )}{( 2 b - 1 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(2 b - 1)^{2} = (2 b - 1) (2 b - 1)

= \frac{a ( 2 b - 1 )}{( 2 b - 1 ) ( 2 b - 1 )}

Cancel the common factor:

2 b - 1

= \frac{a}{2 b - 1}

1 0^{2} + 1 2^{2}

x^{2} + 16 x + 50 = 0

2 (x - 4) = 6 (x + 2)

h^{2} - 4 h + 4 = 18

t^{2} - 21 t + 110 = 0

What is ((2ab-a))/((4b^2-4b+1)) ?
The solution to ((2ab-a))/((4b^2-4b+1)) is a/(2b-1)