What is factor 8j^3+4j^2+14j+7 ?

The solution to factor 8j^3+4j^2+14j+7 is (2j+1)(4j^2+7)

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factor 8j^3+4j^2+14j+7

factor

8 j^{3} + 4 j^{2} + 14 j + 7

(2 j + 1) (4 j^{2} + 7)

Solution steps

8 j^{3} + 4 j^{2} + 14 j + 7

= (8 j^{3} + 4 j^{2}) + (14 j + 7)

Factor out

4 j^{2}

from

8 j^{3} + 4 j^{2} : 4 j^{2} (2 j + 1)

Factor out

7

from

14 j + 7 : 7 (2 j + 1)

= 4 j^{2} (2 j + 1) + 7 (2 j + 1)

Factor out common term

2 j + 1

= (2 j + 1) (4 j^{2} + 7)

4 (p - 4) - (p + 7) = 5 (p - 3)

(\frac{9}{5})^{- 1}

(6 - 8 i)^{2}

4 (\frac{1}{2} t - 2) > 2 (t - 3)

4 k - 8032 = 5 (2283.4) - 8032

What is factor 8j^3+4j^2+14j+7 ?
The solution to factor 8j^3+4j^2+14j+7 is (2j+1)(4j^2+7)