What are the solutions to the equation r^2+3r-7=0 ?

The solutions to the equation r^2+3r-7=0 are r=(-3+sqrt(37))/2 ,r=(-3-sqrt(37))/2

Find the zeros of r^2+3r-7=0

The zeros of r^2+3r-7=0 are r=(-3+sqrt(37))/2 ,r=(-3-sqrt(37))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 3 r - 7 = 0

r = \frac{- 3 + 37}{2}, r = \frac{- 3 - 37}{2}

Decimal Notation

r = 1.54138 \dots, r = - 4.54138 \dots

Solution steps

r^{2} + 3 r - 7 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 7) = 37

r_{1, 2} = \frac{- 3 \pm 37}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 3 + 37}{2 \cdot 1}, r_{2} = \frac{- 3 - 37}{2 \cdot 1}

r = \frac{- 3 + 37}{2 \cdot 1} : \frac{- 3 + 37}{2}

r = \frac{- 3 - 37}{2 \cdot 1} : \frac{- 3 - 37}{2}

The solutions to the quadratic equation are:

r = \frac{- 3 + 37}{2}, r = \frac{- 3 - 37}{2}

x^{2} - x - 12 \geq 0

15 x^{5} - 72 x^{3} - 108 x

\frac{3 x + 1}{4} - \frac{5 x - 2}{7} = \frac{1}{14}

2 - 11 x^{2} - 8 x + 9 x^{2}

676

What are the solutions to the equation r^2+3r-7=0 ?
The solutions to the equation r^2+3r-7=0 are r=(-3+sqrt(37))/2 ,r=(-3-sqrt(37))/2
Find the zeros of r^2+3r-7=0
The zeros of r^2+3r-7=0 are r=(-3+sqrt(37))/2 ,r=(-3-sqrt(37))/2