What is (16m^4-81n^4)/(2m-3n) ?

The solution to (16m^4-81n^4)/(2m-3n) is (4m^2+9n^2)(2m+3n)

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simplify (16m^4-81n^4)/(2m-3n)

simplify

\frac{16 m ^{4} - 81 n ^{4}}{2 m - 3 n}

(4 m^{2} + 9 n^{2}) (2 m + 3 n)

Solution steps

\frac{16 m ^{4} - 81 n ^{4}}{2 m - 3 n}

16 m^{4} = (4 m^{2})^{2}

81 n^{4} = (9 n^{2})^{2}

= \frac{( 4 m ^{2} ) ^{2} - ( 9 n ^{2} ) ^{2}}{2 m - 3 n}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 m^{2})^{2} - (9 n^{2})^{2} = (4 m^{2} + 9 n^{2}) (4 m^{2} - 9 n^{2})

= \frac{( 4 m ^{2} + 9 n ^{2} ) ( 4 m ^{2} - 9 n ^{2} )}{2 m - 3 n}

Factor

4 m^{2} - 9 n^{2} : (2 m + 3 n) (2 m - 3 n)

= \frac{( 4 m ^{2} + 9 n ^{2} ) ( 2 m + 3 n ) ( 2 m - 3 n )}{2 m - 3 n}

Cancel the common factor:

2 m - 3 n

= (4 m^{2} + 9 n^{2}) (2 m + 3 n)

\frac{1}{2} + \frac{3}{2} + 6 - 3

2 k^{2} - 16 k - 40

4 x > 8

7 y^{2} + 15 y + 2

3 n^{2} - 19 n - 3010

What is (16m^4-81n^4)/(2m-3n) ?
The solution to (16m^4-81n^4)/(2m-3n) is (4m^2+9n^2)(2m+3n)