What are the solutions to the equation 2w^2+3w-77=0 ?

The solutions to the equation 2w^2+3w-77=0 are w= 11/2 ,w=-7

Find the zeros of 2w^2+3w-77=0

The zeros of 2w^2+3w-77=0 are w= 11/2 ,w=-7

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2 w^{2} + 3 w - 77 = 0

w = \frac{11}{2}, w = - 7

Decimal Notation

w = 5.5, w = - 7

Solution steps

2 w^{2} + 3 w - 77 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 77 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 77) = 25

w_{1, 2} = \frac{- 3 \pm 25}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 3 + 25}{2 \cdot 2}, w_{2} = \frac{- 3 - 25}{2 \cdot 2}

w = \frac{- 3 + 25}{2 \cdot 2} : \frac{11}{2}

w = \frac{- 3 - 25}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

w = \frac{11}{2}, w = - 7

5 x^{2} + 3 x + 8 = 0

\frac{2 x - 1}{3} > x - 5 and 3 x + 4 < \frac{7 x + 9}{2}

1 - (\frac{17}{20})^{2}

5 y + 3 > - 7 y + 13

n^{2} + 3 n - 12 = 6

What are the solutions to the equation 2w^2+3w-77=0 ?
The solutions to the equation 2w^2+3w-77=0 are w= 11/2 ,w=-7
Find the zeros of 2w^2+3w-77=0
The zeros of 2w^2+3w-77=0 are w= 11/2 ,w=-7