What are the solutions to the equation 3n^2-2n-5=0 ?

The solutions to the equation 3n^2-2n-5=0 are n= 5/3 ,n=-1

Find the zeros of 3n^2-2n-5=0

The zeros of 3n^2-2n-5=0 are n= 5/3 ,n=-1

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3 n^{2} - 2 n - 5 = 0

n = \frac{5}{3}, n = - 1

Decimal Notation

n = 1.66666 \dots, n = - 1

Solution steps

3 n^{2} - 2 n - 5 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 5) = 8

n_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 3}, n_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 3}

n = \frac{- ( - 2 ) + 8}{2 \cdot 3} : \frac{5}{3}

n = \frac{- ( - 2 ) - 8}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

n = \frac{5}{3}, n = - 1

6 x^{2} - 4 = 0

(x^{\frac{4}{3}}) (x^{- \frac{2}{5}}) (x^{\frac{3}{5}})

\frac{1}{2} - x < 2

12 x y^{2} - 108 x

8 + x^{3}

What are the solutions to the equation 3n^2-2n-5=0 ?
The solutions to the equation 3n^2-2n-5=0 are n= 5/3 ,n=-1
Find the zeros of 3n^2-2n-5=0
The zeros of 3n^2-2n-5=0 are n= 5/3 ,n=-1