What are the solutions to the equation 4x^2+16x+17=0 ?

The solutions to the equation 4x^2+16x+17=0 are x=-2+i 1/2 ,x=-2-i 1/2

Find the zeros of 4x^2+16x+17=0

The zeros of 4x^2+16x+17=0 are x=-2+i 1/2 ,x=-2-i 1/2

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4 x^{2} + 16 x + 17 = 0

x = - 2 + i \frac{1}{2}, x = - 2 - i \frac{1}{2}

Solution steps

4 x^{2} + 16 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 17}{2 \cdot 4}

Simplify

1 6^{2} - 4 \cdot 4 \cdot 17 : 4 i

x_{1, 2} = \frac{- 16 \pm 4 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 4 i}{2 \cdot 4}, x_{2} = \frac{- 16 - 4 i}{2 \cdot 4}

x = \frac{- 16 + 4 i}{2 \cdot 4} : - 2 + i \frac{1}{2}

x = \frac{- 16 - 4 i}{2 \cdot 4} : - 2 - i \frac{1}{2}

The solutions to the quadratic equation are:

x = - 2 + i \frac{1}{2}, x = - 2 - i \frac{1}{2}

x^{4} - 15 x^{2} - 16

\frac{2}{3} + \frac{3}{4}

(\frac{1}{3})^{\frac{2}{3}}

e^{- \frac{0.27}{0.5}}

x^{2} + 12 x - 10 = 0

What are the solutions to the equation 4x^2+16x+17=0 ?
The solutions to the equation 4x^2+16x+17=0 are x=-2+i 1/2 ,x=-2-i 1/2
Find the zeros of 4x^2+16x+17=0
The zeros of 4x^2+16x+17=0 are x=-2+i 1/2 ,x=-2-i 1/2